How to check if array contains a number in Java with output

Category : Java | Sub Category : Java Programs | By Prasad Bonam Last updated: 2023-08-14 12:51:35 Viewed : 545

To check if an array contains a specific number in Java, you can loop through the array and compare each element with the target number. Here is how you can do it, along with example outputs:

1. Using a Loop:

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public class ArrayContainsNumber {
    public static void main(String[] args) {
        int[] array = {5, 8, 10, 12, 15};
        int targetNumber = 10;

        boolean contains = containsNumber(array, targetNumber);

        if (contains) {
            System.out.println("Array contains the number " + targetNumber);
        } else {
            System.out.println("Array does not contain the number " + targetNumber);
        }
    }

    public static boolean containsNumber(int[] arr, int target) {
        for (int num : arr) {
            if (num == target) {
                return true;
            }
        }
        return false;
    }
}

Output:

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Array contains the number 10

2. Using Arrays.asList() and contains() (for Integer arrays): Note that this approach only works for arrays of object types, like Integer, not for primitive data types like int.

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import java.util.Arrays;

public class ArrayContainsNumber {
    public static void main(String[] args) {
        Integer[] array = {5, 8, 10, 12, 15};
        Integer targetNumber = 10;

        boolean contains = Arrays.asList(array).contains(targetNumber);

        if (contains) {
            System.out.println("Array contains the number " + targetNumber);
        } else {
            System.out.println("Array does not contain the number " + targetNumber);
        }
    }
}

Output:

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Array contains the number 10

Please note that the first approach using a loop is applicable to both primitive data type arrays (int[]) and arrays of object types (Integer[]). The second approach using Arrays.asList() is specific to arrays of object types.