## Java program to find largest number in an array

Category : Java | Sub Category : Java Programs from Coding Interviews | By Prasad Bonam Last updated: 2021-01-02 14:36:30 Viewed : 732

This example shows you how to find largest or maximum number in an array

Step 1:

Initialize array value

Step 2:  (int max = a[0];)

Initialize max value as arrays first value

Step 3: (for int i = 1; i < a.length; i++ )

Iterate array using a for loop (exclude arrays first position 0, since it was assumed as max value)

Step 4: if(a[i] > max)

Use if condition to compare array current value with max value, if current array value is greater than max then assign array current value as max (max = a[i];).

Step 5:

Continue the loop and resign the max value if array current value is greater than max

Program

`class LargestNumber{	public static void main(String args[])	{		int[] a = new int[] { 20, 30, 50, 4, 71, 100};		int max = a[0];		for(int i = 1; i < a.length;i++)		{			if(a[i] > max)			{				max = a[i];			}		}				System.out.println("The Given Array Element is:");		for(int i = 0; i < a.length;i++)		{			System.out.println(a[i]);		}				System.out.println("From The Array Element Largest Number is:" + max);	}}`

Output

The Given Array Element is:
20
30
50
4
71
100
From The Array Element Largest Number is:100